Assuming that the distribution Essay

1. Assuming that the distribution is normal for weight relative to the ideal and 99% of the male participants scored amid (53.68, 64.64), where did 95% of the set for weight relative to the ideal lie? Round your resolution to 2 denary places. x=5.48, SD=22.935.48+1.96(22.93) = 170.59925.48-1.96(22.93)=80.7136(80.71,170.60)2. Which of the following values from Table 1 tells us about variability of the make headway in a distribution? c. 22.573. Assuming that the distribution for General Health Perceptions is normal, 95% of the females gobs around the fuddled were between what values? Round your answer to two decimal places. x=39.71, SD=25.4639.71+1.96(25.46) = 89.611639.71-1.96(25.46) = -10.1916(-10.19, 89.61)4. Assuming that the distribution of scores for Pain is normal, 95% of the mens scores around the suppose were between what two values? Round your answer to two decimal places. x=52.53, SD=30.9052.53+1.96(30.90) = 113.09452.53-1.96(30.90) = -8.034(-8.03, 113.09)5. Were the body image scores significantly contrastive for women versus men? Provide a rationale for your answer. Yes, body image scores were significantly higher for women (73.1 17.0) than men (60.2 17.0).6. Assuming that the distribution of Mental Health scores for men is normal, where are 99% of the mens mental health scores around the mean in this distribution? Round your answer to two decimal places. x= 57.09, SD=23.7257.09+2.58(23.72)= 118.287657.09-2.58(23.72)= -4.1076(-4.11, 118.29)7. Assuming that the distribution of scores for Physical function in women is normal, where are 99% of the womens scores around the mean in this distribution? Round your answer to two decimal places. X= 65.20, SD=29.79 65.20+2.58(29.79) = 142.058265.20-2.58(29.79) = -11.6582(-11.66, 142.06)8. Assuming that the distribution of scores is normal, 99% of HIV-positive body image scores around the mean were between what two values? Round your answer to two decimal places. torso image scores for Male x= 60 .22, SD=16.98 Female x= 73.07, SD= 16.93 Male 60.22+2.58(16.98)= 104.028460.22-2.58(16.98)= 16.4116Female 73.07+2.58(16.93)= 116.749473.07-2.58(16.93)= 29.3906Male and Female HIV+ Body Image scores combined are between (16.41, 116.75)9. Assuming that the distribution of scores for Role Functioning is normal, 99% of the mens scores around the mean were between what values? Round your answer to two decimal places. x=50.00, SD=46.2950.00+2.58(46.29)= 169.428250.00-2.58(46.29)=-69.4282(-69.43,169.43)